Util_Cap_Example

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Capacity and Utilization Example:

Consider a station with two identical machines in parallel. Let,

r_a = rate of arrival to the station = 20 parts / hr.
r_o = rate of processing of each station (unadjusted capacity) = 12 parts / hr.
A = availability of each machine = 0.95
r_e= effective processing rate = r_o x A = 12 * 0.95 = 11.4 parts / hr.

Then the capacity of the station is the long term processing rate of the station, that is of the two machines combined:

Capacity = 2 * r_e = 2 * 11.4 = 22.8 parts / hr.

The utilization of the station is

u = Rate of arrival to station / Station Capacity = 20 / 22.8 = 87.7%